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自己研究的3种静态实现交叉表方法,动态仍在学习。。。
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方案一
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USE stuDBTest
GO
SET NOCOUNT ON
select stuNo=jHS.stuNo,java成绩=jHS.java,HTML成绩=jHS.HTML,SQL成绩=jHS.SQL,C#成绩=C#.Score
from
(select stuNo=jH.stuNo,java=jH.java,HTML=jH.HTML,SQL=SQL.Score
from
(select stuNo=java.stuNo,java=java.Score,HTML=HTML.Score
from
(select stuNo,Score from stuTests where SubjectID=
(select SubjectID from stuSubject where SubjectName=’Java’)) java,
(select stuNo,Score from stuTests where SubjectID=
(select SubjectID from stuSubject where SubjectName=’HTML’)) HTML
where java.stuNo=HTML.stuNo) jH,
(select stuNo,Score from stuTests where SubjectID=
(select SubjectID from stuSubject where SubjectName=’SQL’)) SQL
where jH.stuNo=SQL.stuNo) jHS,
(select stuNo,Score from stuTests where SubjectID=
(select SubjectID from stuSubject where SubjectName=’C#’)) C#
where jHS.stuNo=C#.stuNo
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方案二
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select stuNo=jHSC.stuNo,
java成绩=isnull(jHSC.java,0),
HTML成绩=isnull(jHSC.HTML,0),
SQL成绩=isnull(jHSC.SQL,0),
C#成绩=isnull(jHSC.C#,0),
SQLAdvance成绩=isnull(SQLAdvance.score,0)
from
(select stuNo=jHS.stuNo,java=jHS.java,HTML=jHS.HTML,SQL=jHS.SQL,C#=C#.score
from
(select stuNo=jH.stuNo,java=jH.java,HTML=jH.HTML,SQL=SQL.score
from
(select stuNo=java.stuNo,java=java.Score,HTML=HTML.Score
from
(select stuNo,Score from stuTests where SubjectID=
(select SubjectID from stuSubject where SubjectName=’Java’)) java –看做表 JAVA
left join
(select stuNo,Score from stuTests where SubjectID=
(select SubjectID from stuSubject where SubjectName=’HTML’)) HTML –看做表 HTML
on java.stuNo=HTML.stuNo) jH –连接JAVA和HTML后看做表jH
left join
(select stuNo,Score from stuTests where SubjectID=
(select SubjectID from stuSubject where SubjectName=’SQL’)) SQL –看做表 SQL
on jH.stuNo=SQL.stuNo) jHS —-连接SQL和jH后看做表jHS
left join
(select stuNo,Score from stuTests where SubjectID=
(select SubjectID from stuSubject where SubjectName=’C#’)) C# –看做表 C#
on jHS.stuNo=C#.stuNo) jHSC –连接C#和jHS后看做表jHSC
left join
(select stuNo,Score from stuTests where SubjectID=
(select SubjectID from stuSubject where SubjectName=’SQLAdvance’)) SQLAdvance on jHSC.stuNo=SQLAdvance.stuNo –连接SQLAdvance和jHSC
GO
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方案三
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–得到科目号
DECLARE @javaID int,@HTMLID int,@SQLID int,@C#ID int,@SQLAdvanceID int
select @javaID=SubjectID from stuSubject where SubjectName=’Java’
select @HTMLID=SubjectID from stuSubject where SubjectName=’HTML’
select @SQLID=SubjectID from stuSubject where SubjectName=’SQL’
select @C#ID=SubjectID from stuSubject where SubjectName=’C#’
select @SQLAdvanceID=SubjectID from stuSubject where SubjectName=’SQLAdvance’
–实现交叉表
select stuNo,
Java成绩=sum(case subjectID WHEN @javaID then Score else 0 end),
HTML成绩=sum(case subjectID WHEN @HTMLID then Score else 0 end),
SQL成绩=sum(case subjectID WHEN @SQLID then Score else 0 end),
C#成绩=sum(case subjectID WHEN @C#ID then Score else 0 end),
SQLAdvance成绩=sum(case subjectID WHEN @SQLAdvanceID then Score else 0 end)
from stuTests T
group by stuNO
GO
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初始化数据
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use master
go
xp_cmdshell ‘mkdir d:\project’, NO_OUTPUT –创建文件夹project,xp_cmdshell为系统存储过程
–检验数据库是否存在,如果为真,删除此数据库–
IF EXISTS(SELECT NAME FROM master.dbo.SYSDATABASES WHERE NAME=N’stuDBTest’)
DROP DATABASE stuDBTest
GO
–创建数据库–
CREATE DATABASE stuDBTest
ON
(NAME=N’stuDB’,
FILENAME=’d:\project\stuDBTest.mdf’,
SIZE=5mb,
MAXSIZE=10mb,
FILEGROWTH=15%)
LOG ON
(NAME=N’stuDB_log’,
FILENAME=’d:\project\stuDBTest_log.ldf’,
SIZE=2mb,
MAXSIZE=4mb,
FILEGROWTH=15%)
GO
USE stuDBTest
GO
SET NOCOUNT ON
–创建学员表stuInfo
IF EXISTS(SELECT NAME FROM SYSOBJECTS WHERE NAME=N’stuInfo’)
DROP TABLE stuInfo
GO
CREATE TABLE stuInfo
(stuName NVARCHAR(20) NOT NULL,
stuNo NCHAR(6) NOT NULL,
stuSex NCHAR(4) NOT NULL,
stuAge SMALLINT NOT NULL,
stuSeat SMALLINT IDENTITY(1,1),
stuAddress NTEXT)
GO
ALTER TABLE stuInfo
ADD CONSTRAINT PK_stuNo PRIMARY KEY(stuNo),
CONSTRAINT CK_stuNo CHECK(stuNo LIKE ‘S253[0-9][0-9]‘),
CONSTRAINT CK_stuSex CHECK(stuSex=’男’ OR stuSex=’女’),
CONSTRAINT CK_stuAge CHECK(stuAge BETWEEN 15 AND 40),
CONSTRAINT CK_stuSeat CHECK(stuSeat<=30),
CONSTRAINT DF_stuAddress DEFAULT (‘地址不详’) FOR stuAddress
GO
–创建科目表
IF EXISTS(SELECT * FROM sysobjects WHERE name=’stuSubject’)
DROP TABLE stuSubject
Go
CREATE TABLE stuSubject — 科目表
(
SubjectID INT IDENTITY (1,1), –ID,自动编号
SubjectName varchar(50) NOT NULL, –科目名称
)
GO
Insert stuSubject(SubjectName) values(‘Java’)
Insert stuSubject(SubjectName) values(‘HTML’)
Insert stuSubject(SubjectName) values(‘SQL’)
Insert stuSubject(SubjectName) values(‘C#’)
Insert stuSubject(SubjectName) values(‘SQLAdvance’)
GO
–创建内测表
IF EXISTS(SELECT * FROM sysobjects WHERE name=’stuTests’)
DROP TABLE stuTests
Go
CREATE TABLE stuTests — 内测表
(
TestID INT IDENTITY (1,1), –ID,自动编号
stuNo CHAR(6) NOT NULL, –学号
SubjectID INT NOT NULL, –科目ID
Score INT NOT NULL –内测成绩
)
GO
INSERT INTO stuInfo(stuName,stuNo,stuSex,stuAge,stuAddress)VALUES(‘张秋丽’,'s25301′,’男’,18,’北京海淀’)
INSERT INTO stuInfo(stuName,stuNo,stuSex,stuAge,stuAddress) VALUES(‘李斯文’,'s25303′,’女’,22,’河南洛阳’)
INSERT INTO stuInfo(stuName,stuNo,stuSex,stuAge) VALUES(‘李文才’,'s25302′,’男’,31)
INSERT INTO stuInfo(stuName,stuNo,stuSex,stuAge,stuAddress) VALUES(‘欧阳俊雄’,'s25304′,’男’,28,’新疆威武哈’)
Insert into stuTests(SubjectID, stuNo, Score)
values(1,’s25301′,50)
Insert into stuTests(SubjectID, stuNo, Score)
values(2,’s25301′,60)
Insert into stuTests(SubjectID, stuNo, Score)
values(3,’s25301′,70)
Insert into stuTests(SubjectID, stuNo, Score)
values(4,’s25301′,80)
Insert into stuTests(SubjectID, stuNo, Score)
values(1,’s25302′,100)
Insert into stuTests(SubjectID, stuNo, Score)
values(2,’s25302′,99)
Insert into stuTests(SubjectID, stuNo, Score)
values(3,’s25302′,98)
Insert into stuTests(SubjectID, stuNo, Score)
values(4,’s25302′,97)